In the lecture of cost function formula, instead of considering the error average, it is considered the error average divided by two. Why is that? What do we gain by dividing it by 2?

I didn't undertand why divide by 2m is better

Course Q&A Machine Learning Specialization Supervised ML: Regression and Classification

shanup July 17, 2022, 10:23pm 8

I am not sure if that answer is accurate.

Dividing by m is so that the cost function does not depend on the number of samples. Further dividing by 2 helps to cancel out the 2 in the numerator, which appears when we take the derivative of Error^2.

Cost_function formula_Difference between 2*m & m?

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I didn't undertand why divide by 2m is better

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