J = 3a + 3bc \Longrightarrow \frac{\partial J}{\partial b} = 3c, \quad \frac{\partial J}{\partial c} = 3b

And if we follow the lectures way of the chain rule, we’d get the same result, but why did Andrew conclude that \frac{\partial J}{\partial b} = 6, \quad \frac{\partial J}{\partial c} = 9?

What are the values of b and c in the lecture?

1 Like

Got it

b = 3 \Longrightarrow \partial c = 3 \times 3 = 9

c = 2 \Longrightarrow \partial b = 3 \times 2 = 6