C1_W3_Lab06_Gradient_Descent_Soln question about decision boundary

While doing the last cell for this lab, there’s two lines that I don’t understand.
“x0 = -b_out/w_out[0]
x1 = -b_out/w_out[1]”

I don’t understand how and why the equation is like this for deciding the decision boundary. I understand how b_out and w_out values were obtained, but I’m not understanding how doing that equation will give the correct values for the decision boundary.

Screenshot included.

Hello, @Grimmlen417,

Then we need to first think about what is the condition for a line to be a decision boundary.

Look first at our model:

We can say that

Here, we need to focus on the last equation which says that the condition is a line in the x_0-x_1 coordinate system.

To draw a line, you only need to know two points on that line. To find the first point, you may substitute x_0 = 0 and find the corresponding x_1. To find the second one, you may substitute x_1 = 0 and find the corresponding x_0. I will leave those substitutions as your exercises and you can find the answers in your screenshot :wink:

You get two points, you connect them to draw a line, and that’s the line that satisfies the aforementioned condition which is the condition for boundary.

Cheers,
Raymond

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Ohh I see now. Just manipulating that equation to get the two points, x0 and x1.

Thank you!

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You are welcome, @Grimmlen417!