Mistake in Lecture

Hey, I noticed a mistake in the lecture. The lecturer mentions that the system is contradictory, but in reality, it has many solutions.

When you break it down, you’ll see that the equations are consistent with each other. Specifically, you get ( c = 0 ) and ( b = -a ). Since ( a ) can be any value, the system isn’t contradictory at all it actually has infinitely many solutions. So, while it might seem like there’s a contradiction, the system is just more flexible than it appears.

Sorry, but I think the result for the third set looks correct. If you solve the third set of equations, you get:

c = 5
c = 4

So there is no solution. Just subtract the first equation from the second and third to see what I mean.

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But I think set #4 is also Contradictory. If you subtract 2 x the first equation from the second equation you get:

0 = -5

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