I tried what Luis sir talked about in class in python

```
f = lambda n: ((n + 1)/n) ** n
f(1e20) # gives 1.0, not math.e
```

Also I used python because of it always growing nature in number (for example `int`

here is bigger than `int`

of C++)

Also mathematically when n is too big it approaches 0, which leaves 1^n and we all know what would be the value.