Why in this lecture slide we are putting vector Z in to tf.nn.sigmoid when we used softmax?

So In this lecture slide, we can see that this is training neural network with more numerically accurate option. And here logit is a collection vector Z each element just being a z not representing probability.

In that case why are we putting Z into tf.nn.sigmoid? Shouldn’t we always use tf.nn.softmax? So it can do some calculation for each element like e^z1/e^z1 + e^z2 … + e^zn ?

Hello Seungjun @Seungjun_Lee,

Welcome to our community :slight_smile:

From the screenshot, the model has a dense layer of 1 unit as its output layer, so it is actually a simple logistic regression that predicts whether the sample belongs to a class or not, instead of a more general multi-class classification which has more than one unit in its output layer.

The simple binary logistic regression uses a sigmoid, whereas the multi-class uses a softmax. Here it is a simple binary logistic regression.

Cheers,
Raymond

Question pertaining to the original question and the answer. In one of the lecture slides shown here (class 2, week 2, “Improved implementation of softmax”):


It shows the code for what the professor says is a logistic regression. This video goes on and edits the code to use the more numerically accurate option (output is ‘linear’ and from_logits=True is used in the .compile function). However, the output layer remains with units = 10.
Questions on this:
1.) If we are doing a binary logistic regression, I thought the output layer had to be 1 unit, and a multiclassification problem would have the number of units in the output layer equal to the number of possible categories. Did I miss something?
2.) Side question: If we wanted to, could we use the
kernel_regularizer=tf.keras.regularizers.l2(0.1)
variable/input within a layer to make the calculation regularized for binary logistic regression? (I only recall seeing that in use with a multiclass classification problems later in this course).

Thanks.

Hello Navead,

Yes

Yes


The last Dense layer should have had units=1 instead of 10.

Yes, you may use regularizer on any dense layer.

Raymond