slides show y hat value inside the closed curve to be 1, but I think it should be 0 inside and 1 outside.

Hi @Ankur_Agarwal1,

Why should it be 0?

Besides, let me provide a way to justify it. Consider the point of origin (x_1 = x_2 = 0), because at that point, z = b, so if b > 0, then g(z) = g(b) > 0.5. Under the assumption that it classifies as 1 if g(z) > 0.5, we can conclude that, if b>0, the point of origin represents class 1, and by extension, any point on the same side of the boundary as the point of origin represents class 1 (Note that this conclusion bases on that the boundary is as drawn).

Now, would you review the lecture again, and provide any evidence that will support your latest conclusion?

Cheers,

Raymond

No, where the 0’s and 1’s are depends on the signs of the weight values.