check your regularization term.
your error is stating you have implemented the regularization term lambda_ incorrectly to J.
refer the hints below the grader cell.
you code is ending at j = j/2
i
regularizationRegularization just squares each element of the W array and X array and them sums all the squared elements. You can utilize np.square() and np.sum().
Check your codes for J.
While implementing codes for cost is for non-regularized implementation
and then
for regularization implementation
you are probably doing in the incorrect way of first using the regularized implementation and then applying the non-regularized implementation, hence getting this error.
tell me all the codes you wrote for J
tell me the first
Step 1. J code where it mention under the loop below ( notice the position of this code is not same as the other two steps as it comes under loop
step 2 then J = J/2
step 3 then regularized implemented J code
{moderator edit: code removed}
this code is incorrect. Did you try to have a look at the hints below the grader cell where you wrote codes.
hints step by step,
this is not required
Incorrect code, you do not require to sum up b to the regularized implementation of cost J
thanks so much for you it graded all tests is pass
@TMosh Thanks Tom Tom for removing the codes.
Salma don’t post codes next time, I only asked for correcting purpose. It is against community guidelines.
Sorry i will be careful for the next time
hey DEEPTI i am having the same problem
@NATHAN_CHRISTOPHER_M, please see the other thread where you replied.
Hi Salma, could you please share how you made it work? I am facing the same issue.
is your issue resolved???