I’m having a hard time solving the problem above with the “Method of Elimination”. I’m guessing that I need three equations initially, but I’m only able to derive two:

A + B + Z = 10,000 0.02A + 0.03B + 0.04Z = 260

With these two, I divide the second equation by 0.02, which results in:

The third equation you’re missing is that he put twice as much money in savings (your A) as in the Cert of Deposit (your B)
So you also have A = 2B.
Use that in your first equation (the one with A, B, and Z, to eliminate A.

Well, that’s embarrassing… I was aware that A = 2B but didn’t know where to use that information. Seems like we have:

Initial Equations:

{moderator edit - solution removed}

… and the rest is history!

Thank you for clarifying this, I really appreciate it! Please let me know if I can shorten this process or structure it in a more intuitive way. I was expecting to have three equations initially, all containing A in it. It feels to me like the third equation doesn’t really make sense as a declaration initially, but is more of an equation that emerges as you progress. But that could be the perception of a total noob (me).